I found this article on the subject, and decided to turn that data into a visualization, too.
control the terminal.1
。91视频对此有专业解读
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思路：先对 nums2 用单调栈求每个元素的下一个更大值，存入 Map 缓存；再遍历 nums1 直接查 Map 得结果。时间复杂度 O(len1 + len2)。
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Дания захотела отказать в убежище украинцам призывного возраста09:44
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